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14x^2+57x+5=0
a = 14; b = 57; c = +5;
Δ = b2-4ac
Δ = 572-4·14·5
Δ = 2969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(57)-\sqrt{2969}}{2*14}=\frac{-57-\sqrt{2969}}{28} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(57)+\sqrt{2969}}{2*14}=\frac{-57+\sqrt{2969}}{28} $
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